InStr Function
Returns a Variant (Long) specifying the position of the first occurrence of one string within another.
Syntax
InStr([start, ]string1, string2[, compare])
The InStr function syntax has these arguments:
| Part | Description |
|---|---|
| start | Optional. Numeric expression that sets the starting position for each search. If omitted, search begins at the first character position. If start contains Null, an error occurs. The start argument is required if compare is specified. |
| string1 | Required. String expression being searched. |
| string2 | Required. String expression sought. |
| compare | Optional. Specifies the type of string comparison. If compare is Null, an error occurs. If compare is omitted, the Option Compare setting determines the type of comparison. Specify a valid LCID (LocaleID) to use locale-specific rules in the comparison. |
Settings
The compare argument settings are:
| Constant | Value | Description |
|---|---|---|
| vbUseCompareOption | -1 | Performs a comparison using the setting of the Option Compare statement. |
| vbBinaryCompare | 0 | Performs a binary comparison. |
| vbTextCompare | 1 | Performs a textual comparison. |
| vbDatabaseCompare | 2 | Microsoft Access only. Performs a comparison based on information in your database. |
Return Values
| If | InStr returns |
|---|---|
| string1 is zero-length | 0 |
| string1 is Null | Null |
| string2 is zero-length | start |
| string2 is Null | Null |
| string2 is not found | 0 |
| string2 is found within string1 | Position at which match is found |
| start > string2 | 0 |
Remarks
The InStrB function is used with byte data contained in a string. Instead of returning the character position of the first occurrence of one string within another, InStrB returns the byte position.
Example
This example uses the InStr function to return the position of the first occurrence of one string within another.
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